document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=645237>Question 645237</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you go about solving this word problem? The product of two consecutive  integers is three less than three times their sum. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #405404 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=405404\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The product of two consecutive integers is three less than three times their sum.<BR>\n" );
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document.write( "1st: x<BR>\n" );
document.write( "2nd: x+1<BR>\n" );
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document.write( "EQuation:<BR>\n" );
document.write( "x(x+1) = 3(x + (x+1))-3<BR>\n" );
document.write( "------<BR>\n" );
document.write( "x^2+x = 3(2x+1) -3<BR>\n" );
document.write( "x^2+x = 6x+3 -3<BR>\n" );
document.write( "----<BR>\n" );
document.write( "x^2 - 5x = 0<BR>\n" );
document.write( "x(x-5) = 0<BR>\n" );
document.write( "x = 0 or x = 5<BR>\n" );
document.write( "---<BR>\n" );
document.write( "If x = 0, x+1 = 1<BR>\n" );
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document.write( "If x = 5, x+1 = 6<BR>\n" );
document.write( "======================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "==================== </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );