document.write( "Question 59126: Three consecutive integers have the sum of 153. What is the second integer? \n" ); document.write( "
Algebra.Com's Answer #40539 by funmath(2933)\"\" \"About 
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Three consecutive integers have the sum of 153. What is the second integer?
\n" ); document.write( "When we count consecutive integers we're adding 1:
\n" ); document.write( "1,2,3,4,5...
\n" ); document.write( "1,1+1,1+1+1,1+1+1+1,1+1+1+1+1,...
\n" ); document.write( "so
\n" ); document.write( "If the first integer is: x
\n" ); document.write( "Then the second integer is:x+1
\n" ); document.write( "and the third integer is:x+1+1=x+2
\n" ); document.write( "sum means +
\n" ); document.write( "is means =
\n" ); document.write( "(x)+(x+1)+(x+2)=153
\n" ); document.write( "3x+3=153
\n" ); document.write( "3x+3-3=153-3
\n" ); document.write( "3x=150
\n" ); document.write( "3x/3=150/3
\n" ); document.write( "x=50
\n" ); document.write( "The first integer is:x=50
\n" ); document.write( "the second integer is:x+1=50+1=\"highlight%2851%29\"
\n" ); document.write( "The thrid integer is:x+2=50+2=52
\n" ); document.write( ":
\n" ); document.write( "Check is the sum of those digits = to 153?
\n" ); document.write( "50+51+52=153
\n" ); document.write( "153=153 Looks good to me!!!
\n" ); document.write( "Happy Calculating!!!
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