document.write( "Question 644953: In solving the equation (x + 3)(x + 1) = 48, Eric stated that the solution would be
\n" ); document.write( "x + 3 = 48 => x = 45
\n" ); document.write( "or
\n" ); document.write( "(x + 1) = 48 => x = 47
\n" ); document.write( "However, at least one of these solutions fails to work when substituted back into the original equation. Why is that? Please help Eric to understand better; solve the problem yourself, and explain your reasoning.
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Algebra.Com's Answer #405329 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
In solving the equation (x + 3)(x + 1) = 48, Eric stated that the solution would be
\n" ); document.write( "x + 3 = 48 => x = 45
\n" ); document.write( "or
\n" ); document.write( "(x + 1) = 48 => x = 47
\n" ); document.write( "However, at least one of these solutions fails to work when substituted back into the original equation. Why is that? Please help Eric to understand better; solve the problem yourself, and explain your reasoning.
\n" ); document.write( "---
\n" ); document.write( "Although the product of the 2 factos is 48, one of the factors does
\n" ); document.write( "not have to be 48. The factors could be 6 and 8, or 2 and 24, or
\n" ); document.write( "any other combinations factors whose product is 48.
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\n" ); document.write( "Solution:
\n" ); document.write( "(x+3)(x+1) = 48
\n" ); document.write( "x^2 + 4x + 3 = 48
\n" ); document.write( "x^2 + 4x - 45 = 0
\n" ); document.write( "---
\n" ); document.write( "Factor
\n" ); document.write( "x^2 + 9x-5x - 45 = 0
\n" ); document.write( "Factor:
\n" ); document.write( "x(x+9) -5(x+9) = 0
\n" ); document.write( "(x+9)(x-5) = 0
\n" ); document.write( "---
\n" ); document.write( "Since this product is zero, at least one of those factors
\n" ); document.write( "MUST be zero.
\n" ); document.write( "---
\n" ); document.write( "x+9 = 0 OR x-5 = 0
\n" ); document.write( "x = -9 OR x = 5
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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