document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=644837>Question 644837</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x^6-2x^4-x^2+2=0 Am I supposed to factor by grouping here?<BR>\n" );
document.write( "x^4(x^2-2) -1(x^2+2)<BR>\n" );
document.write( "(x^4-1) (x^2-2) (x^2+2)  Did I factor these correctly? <BR>\n" );
document.write( "What would be my next step? Or did I miss a step?<BR>\n" );
document.write( "I am totally lost with this problem.  I am also having problems factoring terms that have higher than one as it's coefficient. Also, numbers with powers due to the zero product property being used.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #405282 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=405282\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^6-2x^4-x^2+2=0<BR>\n" );
document.write( "(x-1) (x+1) (x^2-2) (x^2+1) = 0 </SPAN>\n" );
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