document.write( "Question 644822: Alfred, Mindy and Casey can mow their lawn in 60 minutes if they work together. If it takes Alfred twice as long as Mindy and Casey take 10 minutes more than Mindy, how long would it take each to mow the lawn alone? \n" ); document.write( "
Algebra.Com's Answer #405265 by nerdybill(7384)\"\" \"About 
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Alfred, Mindy and Casey can mow their lawn in 60 minutes if they work together. If it takes Alfred twice as long as Mindy and Casey take 10 minutes more than Mindy, how long would it take each to mow the lawn alone?
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\n" ); document.write( "Let m = time (mins) it takes Mindy to mow alone
\n" ); document.write( "then
\n" ); document.write( "2m = time (mins) it takes Alfred to mow alone
\n" ); document.write( "m+10 = time (mins) it takes Casey to mow alone
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\n" ); document.write( "from:\"Alfred, Mindy and Casey can mow their lawn in 60 minutes if they work together.\" we get our equation:
\n" ); document.write( "60(1/m + 1/(2m) + 1/(m+10)) = 1
\n" ); document.write( "multiplying both sides by m(2m)(m+10) we get:
\n" ); document.write( "60((2m)(m+10) + m(m+10) + m(2m)) = m(2m)(m+10)
\n" ); document.write( "60(2m^2+20m + m^2+10m + 2m^2) = (2m^2)(m+10)
\n" ); document.write( "60(5m^2+30m) = 2m^3+20m^2
\n" ); document.write( "30(5m^2+30m) = m^3+10m^2
\n" ); document.write( "150m^2+900m = m^3+10m^2
\n" ); document.write( "900m = m^3-140m^2
\n" ); document.write( "0 = m^3-140m^2-900m
\n" ); document.write( "0 = m(m^2-140m-900)
\n" ); document.write( "applying the quadratic formula, we get:
\n" ); document.write( "m = {0, 146.16, -6.16}
\n" ); document.write( "toss out 0 and the negative solution (extraneous) leaving:
\n" ); document.write( "m = 146 mins (Mindy)
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\n" ); document.write( "Alfred:
\n" ); document.write( "2m = 2(146) = 292 mins
\n" ); document.write( "Casey:
\n" ); document.write( "m+10 = 146+10 = 156 mins
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\n" ); document.write( "Details from quadratic formula:
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"ax%5E2%2Bbx%2Bc=0\" (in our case \"1x%5E2%2B-140x%2B-900+=+0\") has the following solutons:
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\n" ); document.write( " \"x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
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\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
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\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%28-140%29%5E2-4%2A1%2A-900=23200\".
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\n" ); document.write( " Discriminant d=23200 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28--140%2B-sqrt%28+23200+%29%29%2F2%5Ca\".
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\n" ); document.write( " \"x%5B1%5D+=+%28-%28-140%29%2Bsqrt%28+23200+%29%29%2F2%5C1+=+146.157731058639\"
\n" ); document.write( " \"x%5B2%5D+=+%28-%28-140%29-sqrt%28+23200+%29%29%2F2%5C1+=+-6.15773105863909\"
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\n" ); document.write( " Quadratic expression \"1x%5E2%2B-140x%2B-900\" can be factored:
\n" ); document.write( " \"1x%5E2%2B-140x%2B-900+=+1%28x-146.157731058639%29%2A%28x--6.15773105863909%29\"
\n" ); document.write( " Again, the answer is: 146.157731058639, -6.15773105863909.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B-140%2Ax%2B-900+%29\"

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