document.write( "Question 59088: A ball is thrown straight up at an initial velocity of 53 feet per second. In the first 1.5 seconds, it travels 42 feet. The formula s= u+v t
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\n" ); document.write( "\n" ); document.write( " represents the vertical distance s that an object travels in t seconds, where u represents the initail velocity of the object an dv represnts the velocity of the object at the end of t seconds. Find the velocity of the ball at the end of 1.5 seconds
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Algebra.Com's Answer #40524 by funmath(2933)\"\" \"About 
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A ball is thrown straight up at an initial velocity of 53 feet per second. In the first 1.5 seconds, it travels 42 feet. The formula \"s=%28u%2Bvt%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( " represents the vertical distance s that an object travels in t seconds, where u represents the initail velocity of the object an dv represnts the velocity of the object at the end of t seconds. Find the velocity of the ball at the end of 1.5 seconds
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\n" ); document.write( "Solve the formula for v, and plug and chug.
\n" ); document.write( "\"2s=2%28u%2Bvt%29%2F2\"
\n" ); document.write( "\"2s=u%2Bvt\"
\n" ); document.write( "\"2s-u=vt\"
\n" ); document.write( "\"%282s-u%29%2Ft=vt%2Ft\"
\n" ); document.write( "\"v=%282s-u%29%2Ft\" u=53, s=42, t=1.5 (units for v:ft/s)
\n" ); document.write( "\"v=%282%2842%29-53%29%2F1.5\"
\n" ); document.write( "\"v=%2884-53%29%2F1.5\"
\n" ); document.write( "\"v=31%2F1.5\"
\n" ); document.write( "v=20.6666667 ft/s
\n" ); document.write( "v=2.1x10 ft/s rounding off to significatant digits. I don't know how much that matters to you.
\n" ); document.write( "Happy Calculating!!!
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