document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=644640>Question 644640</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We're doing maximums and minimums of functions in my precalc class and i'm just not sure what to do with this word problem. If you could please give it a look and get back to me.\r<BR>\n" );
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document.write( "Suppose that the cost of laying cable on land is $20 per meter and the cost of laying cable under water is $30 per meter. In the diagram below the river is 50 meters wide and the distance AC is 100 meters. Express the cost of laying cable from A to B as a function of the distance from A to P. Use a graphing utility to find the location of P that minimizes the cost of laying the cable from A to B.\r<BR>\n" );
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document.write( "I'm not really sure how to do any of this. I figure that the distance a to p is 100-x but i'm not sure where to go from there.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #405217 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=405217\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Suppose that the cost of laying cable on land is $20 per meter and the<BR>\n" );
document.write( " cost of laying cable under water is $30 per meter.<BR>\n" );
document.write( " In the diagram below the river is 50 meters wide and the distance AC<BR>\n" );
document.write( " is 100 meters.<BR>\n" );
document.write( " Express the cost of laying cable from A to B as a function of the distance<BR>\n" );
document.write( " from A to P.<BR>\n" );
document.write( " Use a graphing utility to find the location of P that minimizes the cost<BR>\n" );
document.write( " of laying the cable from A to B.<BR>\n" );
document.write( "I'm not really sure how to do any of this. I figure that the distance a to p is 100-x but i'm not sure where to go from there. <BR>\n" );
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document.write( "If I understand this correctly? <BR>\n" );
document.write( "  x = dist from A to P and,<BR>\n" );
document.write( " (100-x) = dist from P to c which is directly across form B<BR>\n" );
document.write( "  The cable under water will be from P to B<BR>\n" );
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document.write( "Total Cost = Land cost + water cost<BR>\n" );
document.write( "C(x) = 20x + 30<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%28100-x%29%5E2+%2B+50%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28%28100-x%29%5E2+%2B+50%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "the graph<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-50%2C+150%2C+-1000%2C+5000%2C+20x%2B30%2Asqrt%28%28100-x%29%5E2%2B50%5E2%29%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Ti83 gave a minimum cost of $3,118 when x = 55.3 meters </SPAN>\n" );
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