document.write( "Question 59074: Two airplanes leave the Atalnta airport at th esame time, traveling in opposite directions. One plane travels 30 miles per hour faster than the other. After 3 hours, the planes are 3150 miles apart. what is the rate of each plane? \n" ); document.write( "
Algebra.Com's Answer #40519 by funmath(2933)\"\" \"About 
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Two airplanes leave the Atalnta airport at the same time, traveling in opposite directions. One plane travels 30 miles per hour faster than the other. After 3 hours, the planes are 3150 miles apart. what is the rate of each plane?
\n" ); document.write( "distance (d) = rate (r)* time(t) \"highlight%28d=rt%29\"
\n" ); document.write( "Time for both planes is: t=3
\n" ); document.write( "One planes rate (r) is: x+30
\n" ); document.write( "The other's rate (r) is: x
\n" ); document.write( "The distance of one plane is: rt=tr=3(x+30)
\n" ); document.write( "The distance of the other is: rt=tr=3x
\n" ); document.write( "Since they're going in oppostie directions, if we add their two distances together you get: 3150
\n" ); document.write( ":
\n" ); document.write( "The equation to solve is:
\n" ); document.write( "3(x+30)+3x=3150
\n" ); document.write( "3x+90+3x=3150
\n" ); document.write( "6x+90=3150
\n" ); document.write( "6x+90-90=3150-90
\n" ); document.write( "6x=3060
\n" ); document.write( "6x/6=3060/6
\n" ); document.write( "x=510
\n" ); document.write( ":
\n" ); document.write( "One plane flew at: x+30=510+30=540 mph
\n" ); document.write( "The other flew at: x=510 mph
\n" ); document.write( ":
\n" ); document.write( "Check if both planes flew at that rate for 3 hours would they be 3150 miles apart?
\n" ); document.write( "3(540)+3(510)=3150
\n" ); document.write( "1620+1530=3150
\n" ); document.write( "3150=3150 We're right!!
\n" ); document.write( "Happy Calculating!!!
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