document.write( "Question 644388: Denise and Joan are 28.5 miles apart. at exactly the same time, the begin traveling towards each other. Denise speed is 5 mph less than twice joan's speed. they meet in 90 minutes. How fast does each travel? \n" ); document.write( "
Algebra.Com's Answer #405140 by ankor@dixie-net.com(22740)\"\" \"About 
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Denise and Joan are 28.5 miles apart.
\n" ); document.write( " at exactly the same time, the begin traveling towards each other.
\n" ); document.write( " Denise speed is 5 mph less than twice joan's speed.
\n" ); document.write( " they meet in 90 minutes. How fast does each travel?
\n" ); document.write( ":
\n" ); document.write( "Since we will be dealing mph, change 90 min to 1.5 hrs
\n" ); document.write( ":
\n" ); document.write( "s = Joan's speed
\n" ); document.write( "then it says \"Denise speed is 5 mph less than twice Joan's speed\", therefore
\n" ); document.write( "(2s-5) = Denise's speed
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation, dist = time * speed
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\n" ); document.write( "J's dist + D's dist = 28.5 mi
\n" ); document.write( "1.5s + 1.5(2s-5) = 28.5
\n" ); document.write( "1.5s + 3s - 7.5 = 28.5
\n" ); document.write( "4.5s = 28.5 + 7.5
\n" ); document.write( "4.5s = 36
\n" ); document.write( "s = 36/4.5
\n" ); document.write( "s = 8 mph is J's speed
\n" ); document.write( "then
\n" ); document.write( "2(8)-5 = 11 mph is D's speed
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this out by finding distance each traveled.
\n" ); document.write( "1.5(8) = 12
\n" ); document.write( "1.5(11) = 16.5
\n" ); document.write( "----------------
\n" ); document.write( "total dist: 18.5 \n" ); document.write( "
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