document.write( "Question 644568: Can you show me the steps to solving this and how to set up an equation to solve it?
\n" ); document.write( "Sarah and John are driving in opposite direction on a straight road. John is driving fifteen miles per hour faster than Sarah. After three hours they are 375 miles apart. How fast were Sarah and John traveling?
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Algebra.Com's Answer #405139 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
With this type of problem, I like to think of
\n" ); document.write( "one of them standing still and the other one
\n" ); document.write( "moving at the sum of their speeds
\n" ); document.write( "Let Sarah's speed = \"+s+\" mi/hr
\n" ); document.write( "John's speed = \"+s+%2B+15+\" mi/hr
\n" ); document.write( "-----------
\n" ); document.write( "The equation of motion is
\n" ); document.write( "\"+375+=+%28+s+%2B+s+%2B+15+%29%2A3+\"
\n" ); document.write( "\"+375+=+%28+2s+%2B+15+%29%2A3+\"
\n" ); document.write( "\"+375+=+6s+%2B+45+\"
\n" ); document.write( "\"+6s+=+330+\"
\n" ); document.write( "\"+s+=+55+\"
\n" ); document.write( "\"+s+%2B+15+=+70+\"
\n" ); document.write( "Sarah is traveling at 55 mi/hr
\n" ); document.write( "John is traveling at 70 mi/hr
\n" ); document.write( "check answer:
\n" ); document.write( "Sarah's distance = \"+55%2A3+\"
\n" ); document.write( "\"+55%2A3+=+165+\" mi
\n" ); document.write( "John's distance = \"+70%2A3+\"
\n" ); document.write( "\"+70%2A3+=+210+\" mi
\n" ); document.write( "\"+165+%2B+210+=+375+\" as it should
\n" ); document.write( "OK
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