document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=644551>Question 644551</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -4/(x+4)=-3/(x+6) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #405107 by </B><A HREF=/tutors/aboutme.mpl?userid=tools><B>tools(3)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tools><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=405107\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -4/[x+4]=-3/[x+6] first equatin dem to zero by taking -3/[x+6] to the RHS. -4 /[x+4] + 3/[x+6] = 0 *then the lcm of the both is [x+4][x+6] then it becomes { -4[x+6] + 3[x+4] }/ [x+4][x+6] = 0 *then cross mutiply -4x-24+3x+12=0.therefore -x-12=0 then x= -12 </SPAN>\n" );
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