document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=59066>Question 59066</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve each of the following systems by substitution.\r<BR>\n" );
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document.write( "5x - 2y=-5<BR>\n" );
document.write( " y - 5x = 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #40510 by </B><A HREF=/tutors/aboutme.mpl?userid=funmath><B>funmath(2933)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=funmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=40510\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve each of the following systems by substitution.\r<BR>\n" );
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document.write( "L1) 5x - 2y=-5<BR>\n" );
document.write( "L2)   y - 5x = 3<BR>\n" );
document.write( "Solve L2 for y (because y doesn't have a coefficient to worry about dividing)  and substitute that in for y in L1 and solve L1 for x:<BR>\n" );
document.write( "L2) y-5x+5x=5x+3 ----->>> y=5x+3<BR>\n" );
document.write( "L1) 5x-2(5x+3)=-5<BR>\n" );
document.write( "5x-10x-6=-5<BR>\n" );
document.write( "-5x-6=-5<BR>\n" );
document.write( "-5x-6+6=-5+6<BR>\n" );
document.write( "-5x=1<BR>\n" );
document.write( "-5x/-5=1/-5<BR>\n" );
document.write( "x=-1/5<BR>\n" );
document.write( "Plug this value into L2 and solve for y:<BR>\n" );
document.write( "L2) y-5(-1/5)=3<BR>\n" );
document.write( "y+1=3<BR>\n" );
document.write( "y+1-1=3-1<BR>\n" );
document.write( "y=2<BR>\n" );
document.write( "The solution is (x,y)=(-1/5,2)<BR>\n" );
document.write( "Happy Calculating!!! </SPAN>\n" );
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