document.write( "Question 644439: A large plywood box has a volume of 240 ft^3. Its length is 16 ft greater than its height, and its width is 1 ft less than its height. What are the dimensions of the box? \n" ); document.write( "
Algebra.Com's Answer #405076 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Volume(V) of a box=Length(L)*Width(W)*Height(H) or V=LWH
\n" ); document.write( "Let H=height of the box
\n" ); document.write( "Then L=H+16
\n" ); document.write( "And W=H-1\r
\n" ); document.write( "\n" ); document.write( "Sooooo:
\n" ); document.write( "V=240 ft^3=(H+16)*(H-1)*H expanding, we get:
\n" ); document.write( "H^3+15H^2-16H-240=0 cubic in standard form and we can factor by grouping
\n" ); document.write( "(H^3+15H^2)-16(H+15)=0
\n" ); document.write( "H^2(H+15)-16(H+15)=0
\n" ); document.write( "(H+15)(H^2-16)=0
\n" ); document.write( "(H+15)(H-4)(H+4)=0 so:
\n" ); document.write( "H=-15 &
\n" ); document.write( "H=-4 &
\n" ); document.write( "H=+4----------------------answer\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "V=240=4*20*3=240
\n" ); document.write( "240=240\r
\n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor
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