document.write( "Question 644353: 1/4x+1/3y=11
\n" ); document.write( "1/3x+1/4y=10;
\n" ); document.write( "

Algebra.Com's Answer #405017 by kekegeter (97)\"\" \"About 
You can put this solution on YOUR website!
1. 1/3x + 1/4y =10;\r
\n" ); document.write( "\n" ); document.write( "x/3 + 1/2^2y =10
\n" ); document.write( "x/3 + y/2^2 =10
\n" ); document.write( "4x+3y/3*2 =10
\n" ); document.write( "4x = -3y + 120
\n" ); document.write( "x = 3(-y+40)/4\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "2. 1/4x + 1/3y =11\r
\n" ); document.write( "\n" ); document.write( "1/2^2x + y/3 =11
\n" ); document.write( "x/2^2 + y/3 =11
\n" ); document.write( "3x+ 4y/2^2*3 =11
\n" ); document.write( "3x - 4y + 132
\n" ); document.write( "x = 4(-y+33)/3
\n" ); document.write( "
\n" );