document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1352>Question 1352</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do u solve 3x +15 when x=12<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #405 by </B><A HREF=/tutors/aboutme.mpl?userid=usyim88hk><B>usyim88hk(158)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=usyim88hk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=405\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> When x is 12, then 3x+15 can be rewritten as 3*(12)+15<BR>\n" );
document.write( "because x is 12, so jsut replace x in 3x+15 by 12 which is now <BR>\n" );
document.write( "3(12)+15<BR>\n" );
document.write( "= 36+15<BR>\n" );
document.write( "= 51 </SPAN>\n" );
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