document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=644367>Question 644367</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The base of a triangle is 10 inches more than 2 times the height. If the area of the triangle is 14 square inches, find the base and height. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #404998 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=404998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The base of a triangle is 10 inches more than 2 times the height. If the area of the triangle is 14 square inches, find the base and height.<BR>\n" );
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document.write( "Let the height be \"x\":<BR>\n" );
document.write( "Then the base is \"2x+10\"<BR>\n" );
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document.write( "Area = (1/2)(base)(height)<BR>\n" );
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document.write( "14 = (1/2)(2x+10)(x)<BR>\n" );
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document.write( "2x^2 + 10x - 28= 0<BR>\n" );
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document.write( "x^2 + 5x - 14 = 9<BR>\n" );
document.write( "(x+7)(x-2) = 9<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "x = 2(height)<BR>\n" );
document.write( "2x+10 = 14 (base)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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