document.write( "Question 644355: Solve the equation by the square root property.\r
\n" ); document.write( "\n" ); document.write( "(4x + 3)2 = 5
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Algebra.Com's Answer #404990 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "\"%284x%2B3%29%5E2=5\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"4x%2B3=%22%22%2B-sqrt%285%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"4x%2B3=sqrt%285%29\" or \"4x%2B3=-sqrt%285%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"4x%2B3=sqrt%285%29\" or \"4x%2B3=-sqrt%285%29\" Simplify the square root.\r
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\n" ); document.write( "\n" ); document.write( "\"4x=-3%2Bsqrt%285%29\" or \"4x=-3-sqrt%285%29\" Subtract \"3\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%28-3%2Bsqrt%285%29%29%2F4\" or \"x=%28-3-sqrt%285%29%29%2F4\" Divide both sides by 4.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=%28-3%2Bsqrt%285%29%29%2F4\" or \"x=%28-3-sqrt%285%29%29%2F4\".
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