document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=644184>Question 644184</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measure of angle A is 9 more than  twice the measure of angle B. Ig angle A and angle B are supplementary angles, what is the measure of angle A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #404892 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=404892\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     the measure of angle A is 9 more than twice the measure of angle B. Ig angle A and angle B are supplementary angles, what is the measure of angle A?<BR>\n" );
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document.write( "Let b = measure of angle B<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2b+9 = measure of angle A<BR>\n" );
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document.write( "b + 2b+9 = 180<BR>\n" );
document.write( "3b+9 = 180<BR>\n" );
document.write( "3b = 171<BR>\n" );
document.write( "b = 57 degrees<BR>\n" );
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document.write( "Measure of angle A:<BR>\n" );
document.write( "2b+9 = 2(57)+9 = 114+9 = 123 degrees (answer) </SPAN>\n" );
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