document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=644206>Question 644206</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the numerator of a  rational number is less than its denominator by 3.if the numerator became 3 times and the denominator is increased by 20,the faction became 1\8,find the original faction\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #404891 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=404891\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the numerator of a rational number is less than its denominator by 3.if the numerator became 3 times and the denominator is increased by 20,the faction became 1\8,find the original faction <BR>\n" );
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document.write( "Let d = denominator<BR>\n" );
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document.write( "d-3 = numerator<BR>\n" );
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document.write( "3(d-3)/(d+20) = 1/8<BR>\n" );
document.write( "(3d-9)/(d+20) = 1/8<BR>\n" );
document.write( "cross multiplying:<BR>\n" );
document.write( "8(3d-9) = (d+20)<BR>\n" );
document.write( "24d-72 = d+20<BR>\n" );
document.write( "23d-72 = 20<BR>\n" );
document.write( "23d = 92<BR>\n" );
document.write( "d = 4 (denominator)<BR>\n" );
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document.write( "numerator:<BR>\n" );
document.write( "d-3 = 4-3 = 1<BR>\n" );
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document.write( "answer: 1/4\r<BR>\n" );
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