document.write( "Question 644170: Eva invested a certain amount of money at 7% interest and $1700 more than that amount at 11%. Her total yearly interest was $835. How much did she invest at each rate? \n" ); document.write( "

Algebra.Com's Answer #404860 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = amount invested at 7%
\n" ); document.write( " $\"+x+%2B+1700+\"$ = amount invested at 11%
\n" ); document.write( "given:
\n" ); document.write( " $\"+.07x+%2B+.11%2A%28+x+%2B+1700+%29+=+835+\"$
\n" ); document.write( " $\"+.07x+%2B+.11x+%2B+187+=+835+\"$
\n" ); document.write( " $\"+.18x+=+835+-+187+\"$
\n" ); document.write( " $\"+.18x+=+648+\"$
\n" ); document.write( " $\"+x+=+3600+\"$
\n" ); document.write( " $\"+x+%2B+1700+=+5300+\"$
\n" ); document.write( "She invested $3600 at 7% and $5300 at 11%
\n" ); document.write( "check:
\n" ); document.write( " $\"+.07%2A3600+%2B+.11%2A%28+3600+%2B+1700+%29+=+835+\"$
\n" ); document.write( " $\"+252+%2B+.11%2A5300+=+835+\"$
\n" ); document.write( " $\"+252+%2B+583+=+835+\"$
\n" ); document.write( " $\"+835+=+835+\"$
\n" ); document.write( "OK \n" ); document.write( "

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