document.write( "Question 644074: A rectangle has a width five feet shorter than its length. The perimeter of the rectangle is 112ft. Find the length and width.
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #404857 by Jan Jay Chan(1) ![]() You can put this solution on YOUR website! Let x=length \n" ); document.write( " x-5=width\r \n" ); document.write( "\n" ); document.write( "Get the formula for the perimeter of rectangle \n" ); document.write( " 2L+2W=P \n" ); document.write( "Substitute the x, x-5 and the given perimeter=112ft to the formula \n" ); document.write( " 2(x)+2(x-5)=112 \n" ); document.write( " 2x+2x-10=112 \n" ); document.write( " 4x=122 \n" ); document.write( " x=30.5 \n" ); document.write( "to get width: \n" ); document.write( " x-5 \n" ); document.write( " (30.5)-5 \n" ); document.write( " =25.5\r \n" ); document.write( "\n" ); document.write( " Length=30.5ft \n" ); document.write( " Width=25.5ft\r \n" ); document.write( "\n" ); document.write( "Check the answer: \n" ); document.write( " 2L+2W=p \n" ); document.write( " 2(30.5)+2(25.5)=112 \n" ); document.write( " 61+51=112 \n" ); document.write( " 112=112 \n" ); document.write( " |