document.write( "Question 644074: A rectangle has a width five feet shorter than its length. The perimeter of the rectangle is 112ft. Find the length and width.
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Algebra.Com's Answer #404857 by Jan Jay Chan(1)\"\" \"About 
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Let x=length
\n" ); document.write( " x-5=width\r
\n" ); document.write( "\n" ); document.write( "Get the formula for the perimeter of rectangle
\n" ); document.write( " 2L+2W=P
\n" ); document.write( "Substitute the x, x-5 and the given perimeter=112ft to the formula
\n" ); document.write( " 2(x)+2(x-5)=112
\n" ); document.write( " 2x+2x-10=112
\n" ); document.write( " 4x=122
\n" ); document.write( " x=30.5
\n" ); document.write( "to get width:
\n" ); document.write( " x-5
\n" ); document.write( " (30.5)-5
\n" ); document.write( " =25.5\r
\n" ); document.write( "\n" ); document.write( " Length=30.5ft
\n" ); document.write( " Width=25.5ft\r
\n" ); document.write( "\n" ); document.write( "Check the answer:
\n" ); document.write( " 2L+2W=p
\n" ); document.write( " 2(30.5)+2(25.5)=112
\n" ); document.write( " 61+51=112
\n" ); document.write( " 112=112
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