document.write( "Question 59039: A construction company has submitted bids on two separate state contracts, A and B. The company feels that it has a 60% chance of winning contract A, and a 50% chance of winning contract B. Furthermore, the company believes that it has an 80% chance of winning contract A given that it wins contract B.\r
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document.write( "a) What is the probability that the company will win both contracts?\r
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document.write( "b) What is the probability that the company will win at least one of the two contracts?\r
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document.write( "c) If the company wins contract B, what is the probability that it will not win contract A?\r
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document.write( "d) What is the probability that the company will win at most one of the two contracts?\r
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document.write( "e) What is the probability that the company will win neither contract?
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Algebra.Com's Answer #40484 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The company feels that it has a 60% chance of winning contract A, and a 50% chance of winning contract B. Furthermore, the company believes that it has an 80% chance of winning contract A given that it wins contract B. \n" ); document.write( "P(A)=0.6; P(not A)=0.4 \n" ); document.write( "P(B)=0.5; P(not B)=0.5 \n" ); document.write( "P(A|B)=0.8; P(not A|B)=0.2 \n" ); document.write( "----------------------- \n" ); document.write( "a) What is the probability that the company will win both contracts? \n" ); document.write( "P(A and B)= P(A|B)*P(B)=0.8*0.5=0.4 \n" ); document.write( "Comment: \n" ); document.write( "Notice that P(A and B) is not equal to P(A)*P(B) \n" ); document.write( "because 0.4 is not equal to 0.6*0.5=0.3 \n" ); document.write( "Therefore events A and B are dependent.\r \n" ); document.write( "\n" ); document.write( "b) What is the probability that the company will win at least one of the two contracts? \n" ); document.write( "P(at least one)= 1 - P(win none)= 1- 0.4*0.5=0.8 \r \n" ); document.write( "\n" ); document.write( "c) If the company wins contract B, what is the probability that it will not win contract A? \n" ); document.write( "P(notA |B)= P(not A and B)/P(B) = 0.4*0.5/0.5 = 0.4\r \n" ); document.write( "\n" ); document.write( "d) What is the probability that the company will win at most one of the two contracts? \n" ); document.write( "P(at most one) = 1 - P(both)= 1-0.4 = 0.6\r \n" ); document.write( "\n" ); document.write( "e) What is the probability that the company will win neither contract? \n" ); document.write( "P(not A and notB)=0.4*0.5 = 0.2 \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |