document.write( "Question 58977This question is from textbook discovering geometry- an investigative approach
\n" ); document.write( ": Here is a tiring problem. The diameter of a car tire is approximately 60 centimeters. The warranty is good for 70,000 km. About how many revolutions will the tire make before the warranty is up? More than a million? A billion? \n" ); document.write( "
Algebra.Com's Answer #40483 by ankor@dixie-net.com(22740)\"\" \"About 
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Here is a tiring problem. The diameter of a car tire is approximately 60 centimeters. The warranty is good for 70,000 km. About how many revolutions will the tire make before the warranty is up? More than a million? A billion\r
\n" ); document.write( "\n" ); document.write( "Find the circum of the tire: C = pi*60 = 188.5 cm, or write it 1.885(10^2)
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\n" ); document.write( "Theres 100,000 cm in 1 km, call it 10^5 cm
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\n" ); document.write( "70000 is 7(10^4)
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\n" ); document.write( "7(10^4) * (10^5) = 7(10^9) cm in 70,000 km
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\n" ); document.write( "\"7%2810%5E9%29%2F1.885%2810%5E2%29\" = 3.71(10^7) which is 37.1 million
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