document.write( "Question 644015: how do you understand if you have to simplify the given ratios , for example :[(1+tan^2A)=sec^2A]
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document.write( " or break them down, example :
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document.write( " [(1+tan^2A)=1+(sin^2A/cos^2A) ???????????? \n" );
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Algebra.Com's Answer #404764 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! simplify the given ratios , for example : \n" ); document.write( "(1+tan^2A) = sec^2A \n" ); document.write( "Note: A simpler form always depends on the observer. \n" ); document.write( "Your equation is true because it is one of the Pythagorean \n" ); document.write( "relations for trig functions. \n" ); document.write( "--- \n" ); document.write( "It might be \"simplified\" as follows: \n" ); document.write( "Multiply thru by cos^2(A) and you get: \n" ); document.write( "cos^2(A) + sin^2(A) = 1 \n" ); document.write( "Note: This also is a Pythagorean relation for trig functions. \n" ); document.write( "---- \n" ); document.write( "Is it simpler? That depends on what you know about trig relations. \n" ); document.write( "----- \n" ); document.write( "It simplifies further to 1 = 1 \n" ); document.write( "--- \n" ); document.write( "That definately is \"simpler\". \n" ); document.write( "====================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |