document.write( "Question 643971: how many quarts of pure antifreeze must be added to 2 quarts of a 10% antifreeze solution to obtain a 50% solution? \n" ); document.write( "

Algebra.Com's Answer #404735 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"+x+\"$ = quarts of pure antifreeze needed
\n" ); document.write( " $\"+.1%2A2+=+.2+\"$ quarts of pure antifreeze in 10% solution
\n" ); document.write( " $\"+%28+x+%2B+.2+%29+%2F+%28+x+%2B+2+%29+=+.5+\"$
\n" ); document.write( " $\"+x+%2B+.2+=+.5%2A%28+x+%2B+2+%29+\"$
\n" ); document.write( " $\"+x+%2B+.2+=+.5x+%2B+1+\"$
\n" ); document.write( " $\"+.5x+=+.8+\"$
\n" ); document.write( " $\"+x+=+1.6+\"$
\n" ); document.write( "1.6 quarts of pure antifreeze must be added
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28+1.6+%2B+.2+%29+%2F+%28+1.6+%2B+2+%29+=+.5+\"$
\n" ); document.write( " $\"+1.8+%2F+3.6+=+.5+\"$
\n" ); document.write( " $\"+1.8+=+.5%2A3.6+\"$
\n" ); document.write( " $\"+1.8+=+1.8+\"$
\n" ); document.write( "OK \n" ); document.write( "

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