document.write( "Question 643978: |y|=x+1 please graph. Thank you :) \n" ); document.write( "
Algebra.Com's Answer #404734 by AnlytcPhil(1806)\"\" \"About 
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document.write( "|y| = x + 1\r\n" );
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document.write( "Since |y| ≧ 0, x + 1 ≧ 0, hence x ≧ -1, so we cannot use any values\r\n" );
document.write( "of x less than 1. \r\n" );
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document.write( "So we get a few points.\r\n" );
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document.write( "When x = -1 (the smallest value x can take on) \r\n" );
document.write( "   |y| = -1 + 1\r\n" );
document.write( "   |y| = 0\r\n" );
document.write( "     y = 0, so we have the point (1,0) as the left-most point on the graph.\r\n" );
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document.write( "When x = 0,\r\n" );
document.write( "   |y| = 0 + 1\r\n" );
document.write( "   |y| = 1\r\n" );
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document.write( "There are two values of y that satisfy that, 1 and -1,\r\n" );
document.write( "   so we have the two points (0,1) and (0,-1)\r\n" );
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document.write( "When x = 0,\r\n" );
document.write( "   |y| = 0 + 1\r\n" );
document.write( "   |y| = 1\r\n" );
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document.write( "There are two values of y that satisfy that, 1 and -1,\r\n" );
document.write( "   so we have the two points (0,1) and (0,-1)  \r\n" );
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document.write( "When x = 1,\r\n" );
document.write( "   |y| = 1 + 1\r\n" );
document.write( "   |y| = 2\r\n" );
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document.write( "There are two values of y that satisfy that, 2 and -2,\r\n" );
document.write( "   so we have the two points (1,2) and (1,-2)\r\n" );
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document.write( "That's enough.\r\n" );
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document.write( "We plot what we have:\r\n" );
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document.write( "Then draw the graph:\r\n" );
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document.write( "Edwin
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