document.write( "Question 643805: A diesel train left Washington and traveled
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document.write( "toward Johannesburg at an average speed of
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document.write( "52 mph. A cattle train left two hours later
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document.write( "and traveled in the same direction but with
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document.write( "an average speed of 60 mph. Find the
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document.write( "number of hours the diesel train traveled
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document.write( "before the cattle train caught up \n" );
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Algebra.Com's Answer #404631 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A diesel train left Washington and traveled toward Johannesburg at an \n" ); document.write( " average speed of 52 mph. \n" ); document.write( " A cattle train left two hours later and traveled in the same direction \n" ); document.write( " but with an average speed of 60 mph. \n" ); document.write( " Find the number of hours the diesel train traveled before the cattle train \n" ); document.write( " caught up. \n" ); document.write( ": \n" ); document.write( "Let t = travel time of the diesel train \n" ); document.write( "then \n" ); document.write( "(t-2) = travel time of the cattle train (Left 2 hrs later) \n" ); document.write( ": \n" ); document.write( "When the cattle train catches the diesel, they will have traveled the \n" ); document.write( " same distance. Write a distance equation. Dist = speed * time \n" ); document.write( "52t = 60(t-2) \n" ); document.write( "52t = 60t - 120 \n" ); document.write( "120 = 60t - 52t \n" ); document.write( "120 = 8t \n" ); document.write( "t = 120/8 \n" ); document.write( "t = 15 hrs \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this by finding the distance of each, should be equal \n" ); document.write( "52(15) = 780 mi \n" ); document.write( "60(13) = 780 mi also \n" ); document.write( " |