document.write( "Question 643660: Use matrices to help find a general solution for this system of equations.\r
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document.write( "2x − y + 3z = 5
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document.write( "–x + 4y + 4z = –1 \n" );
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Algebra.Com's Answer #404611 by Edwin McCravy(20086) You can put this solution on YOUR website! \r\n" ); document.write( "This is an under-determined system because there are fewer equations\r\n" ); document.write( "than there are variables. \r\n" ); document.write( "\r\n" ); document.write( "2x - y + 3z = 5\r\n" ); document.write( "-x + 4y + 4z = -1\r\n" ); document.write( "\r\n" ); document.write( "Put in 1's\r\n" ); document.write( "\r\n" ); document.write( " 2x - 1y + 3z = 5\r\n" ); document.write( "-1x + 4y + 4z = -1\r\n" ); document.write( "\r\n" ); document.write( "Write the system as a matrix [by eliminating the letters, putting | for\r\n" ); document.write( "equal signs and enclosing in brackrts]:\r\n" ); document.write( "\r\n" ); document.write( "[ 2 -1 3 | 5]\r\n" ); document.write( "[-1 4 4 | -1]\r\n" ); document.write( "\r\n" ); document.write( "We want to use row operations\r\n" ); document.write( "to make it look like this:\r\n" ); document.write( "\r\n" ); document.write( "[ 1 0 # | #]\r\n" ); document.write( "[ 0 1 # | #]\r\n" ); document.write( "\r\n" ); document.write( "where there are numbers where the #'s are\r\n" ); document.write( "but 1's and 0's as indicated:\r\n" ); document.write( "\r\n" ); document.write( "[ 2 -1 3 | 5]\r\n" ); document.write( "[-1 4 4 | -1]\r\n" ); document.write( "\r\n" ); document.write( "Multiply the 2nd row by 2\r\n" ); document.write( "\r\n" ); document.write( "[ 2 -1 3 | 5]\r\n" ); document.write( "[-2 8 8 | -2]\r\n" ); document.write( "\r\n" ); document.write( "Add the 1st row to the 2nd row to\r\n" ); document.write( "get a 0 in the lower left corner:\r\n" ); document.write( "\r\n" ); document.write( "[ 2 -1 3 | 5]\r\n" ); document.write( "[ 0 7 11 | 3]\r\n" ); document.write( "\r\n" ); document.write( "Multiply the 1st row by 7\r\n" ); document.write( "\r\n" ); document.write( "[14 -7 21 |35]\r\n" ); document.write( "[ 0 7 11 | 3]\r\n" ); document.write( "\r\n" ); document.write( "Add the 2nd row to the 1st row to\r\n" ); document.write( "get a 0 where the -7 is:\r\n" ); document.write( "\r\n" ); document.write( "[14 0 32 |38]\r\n" ); document.write( "[ 0 7 11 | 3]\r\n" ); document.write( "\r\n" ); document.write( "Get a 1 where the 14 is by dividing the \r\n" ); document.write( "1st row through by 14\r\n" ); document.write( "\r\n" ); document.write( "Get a 1 where the 7 is by dividing the\r\n" ); document.write( "2nd row through by 7\r\n" ); document.write( "\r\n" ); document.write( "[ 1 0\n" ); document.write( " |