document.write( "Question 643496: I need some help solving this inequality.\r
\n" ); document.write( "\n" ); document.write( "\"x-5%2F3-x\"<0\r
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Algebra.Com's Answer #404539 by MathTherapy(10555)\"\" \"About 
You can put this solution on YOUR website!
I need some help solving this inequality.\r
\n" ); document.write( "\n" ); document.write( "\"x-5%2F3-x\"<0\r
\n" ); document.write( "\n" ); document.write( "Thank you so much!\r
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\n" ); document.write( "\n" ); document.write( "Before trying to solve this inequality, upon observing it, we realize that whatever x-value one uses, that x-value becomes 0. This is because we are adding x, and also subtracting it (see inequality). This leaves us with: \"-+5%2F3+%3C+0\", which is always, and will forever be TRUE. This means that ANY x-value inserted into the inequality will satisfy it (make it true). \r
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\n" ); document.write( "\n" ); document.write( "Anyway, still working the problem out, we convert the left-side expression to one with a common denominator, 3 to get:\r
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\n" ); document.write( "\n" ); document.write( "\"%283x+-+5+-+3x%29%2F3+%3C+0\" \r
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\n" ); document.write( "\n" ); document.write( "\"-+5%2F3+%3C+0\" ----- 3x - 3x in numerator equals 0
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\n" ); document.write( "\n" ); document.write( "Since this is always true, ANY value that is plugged in for x will satisfy the inequality, thereby leading to the solution x = ALL REALS.\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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