document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=643411>Question 643411</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A passenger train leaves the train depot 2 hours after a freight train left the same depot. The freight train is traveling 20 mph slower than the passenger train. Find the rate of each train, if the passenger train overtakes the freight train in 3 hours. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #404475 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=404475\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A passenger train leaves the train depot 2 hours after a freight train left the same depot. The freight train is traveling 20 mph slower than the passenger train. Find the rate of each train, if the passenger train overtakes the freight train in 3 hours.<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=rate of speed of freight train<BR>\n" );
document.write( "x+20=rate of speed of passenger train<BR>\n" );
document.write( "distance=travel time*rate of speed (same for both trains)<BR>\n" );
document.write( "..<BR>\n" );
document.write( "5x=3(x+20)<BR>\n" );
document.write( "5x=3x+60<BR>\n" );
document.write( "2x=60<BR>\n" );
document.write( "x=30<BR>\n" );
document.write( "x+20=50<BR>\n" );
document.write( "rate of speed of freight train=30 mph<BR>\n" );
document.write( "rate of speed of passenger train=50 mph </SPAN>\n" );
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