document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=642866>Question 642866</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a man who is 42 years old has a son of 12 years old. in how many years will the father be twice as old as his son </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #404449 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=404449\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "a man who is 42 years old has a son of 12 years old. in how many years will the father be twice as old as his son\r<BR>\n" );
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document.write( "Let the amount of years be Y\r<BR>\n" );
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document.write( "Then: 42 + Y = 2(12 + Y)\r<BR>\n" );
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document.write( "42 + Y = 24 + 2Y\r<BR>\n" );
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document.write( "42 - 24 = Y\r<BR>\n" );
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document.write( "Y, or amount of years it'll take for the man to be twice his son's age = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2818%29 ALIGN=MIDDLE  ALT=\"highlight_green%2818%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "You can do the check!!\r<BR>\n" );
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document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com  </SPAN>\n" );
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