document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=643155>Question 643155</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me solve this? If 15 is added to a number, the result is 56 less than twice the number. Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #404376 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=404376\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = the number<BR>\n" );
document.write( "x + 15 = 2x - 56<BR>\n" );
document.write( "subtract x from both sides of the equation and add 56 to both sides of the equation to get:<BR>\n" );
document.write( "x = 71<BR>\n" );
document.write( "that should be your answer.<BR>\n" );
document.write( "add 15 to that number and you get 71 + 15 = 86.<BR>\n" );
document.write( "take 2 times the number and subtract 56 from it to get 2 * 71 - 56 = 142 - 56 = 86<BR>\n" );
document.write( "number checks out so the answer is good.<BR>\n" );
document.write( " </SPAN>\n" );
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