document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=642967>Question 642967</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We have a one pound coffee can.  We will fill that can about 80% full with a grain that contains 12% protein.  We will then fill the remaining 20% with another grain that contains 32% protein.  What is the total percentage of protein the horse will receive a feeding?  How much of each grain (the 12% protein and the 32% protein) should we put into that one pound coffee can so that the horse receives a total of only 15% protein? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #404315 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=404315\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have a one pound coffee can.<BR>\n" );
document.write( " We will fill that can about 80% full with a grain that contains 12% protein.<BR>\n" );
document.write( " We will then fill the remaining 20% with another grain that contains 32% protein. <BR>\n" );
document.write( "What is the total percentage of protein the horse will receive a feeding?<BR>\n" );
document.write( " How much of each grain (the 12% protein and the 32% protein) should we put<BR>\n" );
document.write( " into that one pound coffee can so that the horse receives a total of only<BR>\n" );
document.write( " 15% protein?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Let deal with this in ounces, 16 oz in 1 pound<BR>\n" );
document.write( ".8(16) = 12.8 oz of 12% protein<BR>\n" );
document.write( ".2(16) = 3.2 oz of 32% protein<BR>\n" );
document.write( ":<BR>\n" );
document.write( "\"What is the total percentage of protein the horse will receive a feeding? \"<BR>\n" );
document.write( ".12(12.8) + .32(3.2) = 16x<BR>\n" );
document.write( "1.536 + 1.024 = 16x<BR>\n" );
document.write( "2.56 = 16x<BR>\n" );
document.write( "x = 2.56/16<BR>\n" );
document.write( "x = .16 * 100 = 16% protein in this mixture<BR>\n" );
document.write( ":<BR>\n" );
document.write( "\" How much of each grain (the 12% protein and the 32% protein) should we<BR>\n" );
document.write( " put into that one pound coffee can so that the horse receives a total of <BR>\n" );
document.write( " only 15% protein?<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Let a = amt of 32% grain required to accomplish this<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(16-a) = amt of 12% grain<BR>\n" );
document.write( ":<BR>\n" );
document.write( ".12(16-a) + .32a = .15(16)<BR>\n" );
document.write( "1.92 - .12a + .32a = 2.4<BR>\n" );
document.write( ".20a = 2.4 - 1.92<BR>\n" );
document.write( ".2a = .48<BR>\n" );
document.write( "a = .48/.2<BR>\n" );
document.write( "a = 2.4 oz of 32% grain<BR>\n" );
document.write( "then<BR>\n" );
document.write( "16-2.4 = 13.6 oz of 12% grain </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );