document.write( "Question 642859: There are 15 ‘True or False’ questions in an examination. In how many ways can a student do the examination if he or she can also choose not to answer almost 3 questions? \n" ); document.write( "
Algebra.Com's Answer #404275 by jim_thompson5910(35256)\"\" \"About 
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If the student answers all 15 questions, then there is only one way to do this.\r
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\n" ); document.write( "\n" ); document.write( "If the student skips one question, and exactly one question only, then there are 15 ways to do this (since there are 15 questions to skip).\r
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\n" ); document.write( "\n" ); document.write( "If the student skips two questions, then there are 15 C 2 = 15*14/2 = 105 ways to do this.\r
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\n" ); document.write( "\n" ); document.write( "If the student skips three questions, then there are 15 C 3 = 15*14*13/6 = 455 ways to do this.\r
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\n" ); document.write( "\n" ); document.write( "So if a student can skip at most 3 questions, then there are 1+15+105+455 = 576 different ways to do this. \n" ); document.write( "
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