document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=642736>Question 642736</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 148 ft of fencing was used to make a rectangular fence in a yard. the length of the yard is 6 less than 3 times it's width. What is the length of the yard.\r<BR>\n" );
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document.write( "how would i begin to solve this?\r<BR>\n" );
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document.write( "tried Y = L + 6<3xW\r<BR>\n" );
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document.write( "also tried:<BR>\n" );
document.write( "148= 2L+2W  Y = 2L - 6<BR>\n" );
document.write( ".. would it be 31... did it too many different ways AND CAN'T SEE how to work it out. also came up w. 42...  thank you so much for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #404218 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10552)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=404218\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "148 ft of fencing was used to make a rectangular fence in a yard. the length of the yard is 6 less than 3 times it's width. What is the length of the yard.\r<BR>\n" );
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document.write( "how would i begin to solve this?\r<BR>\n" );
document.write( "\n" );
document.write( "tried Y = L + 6<3xW\r<BR>\n" );
document.write( "\n" );
document.write( "also tried:<BR>\n" );
document.write( "148= 2L+2W  Y = 2L - 6<BR>\n" );
document.write( ".. would it be 31... did it too many different ways AND CAN'T SEE how to work it out. also came up w. 42...  thank you so much for your help.\r<BR>\n" );
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document.write( "Let width be W<BR>\n" );
document.write( "Then length = 3W - 6\r<BR>\n" );
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document.write( "2W + 2L = 148 ----- 2(W + L) = 2(74) ----- Factoring out GCF, 2. This means that:\r<BR>\n" );
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document.write( "W + L = 74\r<BR>\n" );
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document.write( "Now, since W = W, and L = 3W - 6, then W + L = 74 becomes:\r<BR>\n" );
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document.write( "W + 3W - 6 = 74\r<BR>\n" );
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document.write( "4W = 74 + 6\r<BR>\n" );
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document.write( "4W = 80\r<BR>\n" );
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document.write( "W, or width = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=80%2F4 ALIGN=MIDDLE  ALT=\"80%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2820%29 ALIGN=MIDDLE  ALT=\"highlight_green%2820%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > units\r<BR>\n" );
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document.write( "20 + L = 74 ------ Substituting 20 for W \r<BR>\n" );
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document.write( "L = 74 - 20 \r<BR>\n" );
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document.write( "L, or length = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%2854%29 ALIGN=MIDDLE  ALT=\"highlight_green%2854%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > units\r<BR>\n" );
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document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com  </SPAN>\n" );
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