document.write( "Question 7312: Please help me solve this equation: \"%28x%5E2%2B4%29%5E%282%2F3%29+=+25+\" \n" ); document.write( "
Algebra.Com's Answer #4042 by Earlsdon(6294)\"\" \"About 
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Try this:\r
\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B4%29%5E%282%2F3%29+=+25\" Raise both sides to the 3/2 power.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%5E2%2B4%29+=+25%5E%283%2F2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B4+=+125\" Subtract 4 from both sides.\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2+=+121\" Take the square root of both sides.\r
\n" ); document.write( "\n" ); document.write( "\"x+=+11\" or \"x+=+-11\"\r
\n" ); document.write( "\n" ); document.write( "Check:\r
\n" ); document.write( "\n" ); document.write( "\"%2811%5E2+%2B+4%29%5E%282%2F3%29+=+125%5E%282%2F3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"125%5E%282%2F3%29+=+25\"
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