document.write( "Question 642622: 4(4k+2)-8(k-1) ≤ 3(2k+2)-1
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document.write( "Thats a less than or equal to sign incase its hard to see.\r
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document.write( "Type the solution set in interval notation. Thanks to whoever can help! :) \n" );
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Algebra.Com's Answer #404161 by stanbon(75887) ![]() You can put this solution on YOUR website! 4(4k+2)-8(k-1) ≤ 3(2k+2)-1 \n" ); document.write( "16k + 8 - 8k + 8 <= 6k + 6 -1 \n" ); document.write( "-------- \n" ); document.write( "8k +16 <= 6k + 5 \n" ); document.write( "2k <= -11 \n" ); document.write( "k <= -11/2 \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================= \n" ); document.write( " |