document.write( "Question 58918: Two boys trading baseball cards agree that 6 Will Clark cards and 3 Jose Canseco cards are worth the same to them as 2 Nolan Ryan cards. They also agree that 9 Canseco cards are worth the same as 12 Clark cards plus 2 Ryan cards. How many Canseco cards have the same value to them as 2 Ryan cards. \r
\n" ); document.write( "\n" ); document.write( "Can someone help me set this one up and solve it? Thank you.
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Algebra.Com's Answer #40414 by uma(370)\"\" \"About 
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Let W be Will Clark cards , J be Jose Canseco cards and N be Nolan Ryan cards
\n" ); document.write( "Given that 6W + 3J = 2N ----------(1)
\n" ); document.write( "and 12W + 2N = 9J ----------------(2)
\n" ); document.write( "multiplying (1) by 2 gives 12W + 6J = 4N -----------------(3)
\n" ); document.write( " 12W - 9J = - 2N ---------------(2) rearranged\r
\n" ); document.write( "\n" ); document.write( "Subtracting the above two equations we have, 6J + 9J = 4N + 2N
\n" ); document.write( " ==> 15J = 6N
\n" ); document.write( " ==> 5J = 2N [Dividing both the sides by 3]\r
\n" ); document.write( "\n" ); document.write( "Therefore 2 Ryan cards = 5 Canseco cards
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