document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=642398>Question 642398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me- I do not understand how to solve for k.<BR>\n" );
document.write( "(-9/2)k + (-6/5) = 9 - (9/8)k\r<BR>\n" );
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document.write( "Thank you! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #404096 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=404096\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (-9/2)k + (-6/5) = 9 - (9/8)k\r<BR>\n" );
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document.write( "40*(-9/2)k + 40*(-6/5) = 40*9 - 40*(9/8)k ... Multiply EVERY term by the LCD 40 to clear out the fractions.\r<BR>\n" );
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document.write( "20*(-9)k + 8*(-6) = 40*9 - 5*(9)k\r<BR>\n" );
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document.write( "-180k - 48 = 360 - 45k\r<BR>\n" );
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document.write( "-180k=360-45k+48\r<BR>\n" );
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document.write( "-180k+45k=360+48\r<BR>\n" );
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document.write( "-135k=360+48\r<BR>\n" );
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document.write( "-135k=408\r<BR>\n" );
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document.write( "k=(408)/(-135)\r<BR>\n" );
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document.write( "k=-136/45\r<BR>\n" );
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document.write( "So the solution is <font color=\"red\">k = -136/45</font> </SPAN>\n" );
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