document.write( "Question 642387: 2(3x-1)-2x= \n" ); document.write( "
Algebra.Com's Answer #404086 by showe9(33)\"\" \"About 
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First you need to distribute 2(3x-1) and you end up with 6x-2. \r
\n" ); document.write( "\n" ); document.write( "Then you add the -2x from the original problem, and you get 6x-2-2x.\r
\n" ); document.write( "\n" ); document.write( "Now you add the common terms, 6x and -2x.\r
\n" ); document.write( "\n" ); document.write( "The new equation is 4x-2=0.\r
\n" ); document.write( "\n" ); document.write( "Now add 2 to both sides. You get 4x=2.\r
\n" ); document.write( "\n" ); document.write( "Lastly, divide both sides by four to get x=1/2.
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