document.write( "Question 642240: The sum of digits of a two digit number is five.If the digit at ten's place is increased by unity,the digit becomes one-eight of the original number.Find the original number. \n" ); document.write( "

Algebra.Com's Answer #404018 by KMST(5328) $\"\"$ $\"About$

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The tens digit, increased by 1, is still a positive integer.
\n" ); document.write( "If it is $\"1%2F8\"$ of the original number,
\n" ); document.write( "then the original number must be a multiple of $\"8\"$ .
\n" ); document.write( "There are 11 multiples of $\"8\"$ that are two digit numbers:
\n" ); document.write( "16, 24, 32, 40, 48, 56, 64, 72, 80, 88, and 96.
\n" ); document.write( "There is only one of those whose digits add up to $\"5\"$ .
\n" ); document.write( " $\"3%2B2=5\"$
\n" ); document.write( "The number is $\"highlight%2832%29\"$ .
\n" ); document.write( "And, indeed, if you add $\"1\"$ to $\"3\"$ (the tens digit) you get
\n" ); document.write( " $\"1%2F8\"$ of the original number.
\n" ); document.write( " $\"3%2B1=4=32%2F8\"$ \n" ); document.write( "

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