document.write( "Question 642162: How do you solve 3y^2=20 using the quadratic formula? \n" ); document.write( "
Algebra.Com's Answer #403967 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"3y%5E2=20\"\r
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\n" ); document.write( "\n" ); document.write( "\"3y%5E2-20=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"3y%5E2%2B0y-20=0\"\r
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\n" ); document.write( "\n" ); document.write( "Now use the quadratic formula to solve for y\r
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\n" ); document.write( "\n" ); document.write( "In this case, a = 3, b = 0, c = -20, \r
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\n" ); document.write( "\n" ); document.write( "Plug all this into the quadratic formula to get\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%28-%280%29%2B-sqrt%28%280%29%5E2-4%283%29%28-20%29%29%29%2F%282%283%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%280%2B-sqrt%280-%28-240%29%29%29%2F%286%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%28%22%22%2B-sqrt%280%2B240%29%29%2F%286%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%28%22%22%2B-sqrt%28240%29%29%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%28sqrt%28240%29%29%2F6\" or \"y+=+%28-sqrt%28240%29%29%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%284%2Asqrt%2815%29%29%2F6\" or \"y+=+%28-4%2Asqrt%2815%29%29%2F6\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%282%2Asqrt%2815%29%29%2F3\" or \"y+=+%28-2%2Asqrt%2815%29%29%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+2.58198889747161\" or \"y+=+-2.58198889747161\"\r
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\n" ); document.write( "\n" ); document.write( "Note: The last solutions above are approximate
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