document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=641952>Question 641952</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.	How many batting lineups are there for nine players of a baseball team if the center fielder must bat fourth, the second baseman must bat third and the pitcher last? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #403905 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=403905\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You have 3 slots locked up because \"the center fielder must bat fourth, the second baseman must bat third and the pitcher last\". So you have 9 - 3 = 6 players to arrange in 6 slots.\r<BR>\n" );
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document.write( "There are 6! = 6*5*4*3*2*1 = 720 different ways to arrange the 6 remaining players. So there are 720 different lineups. </SPAN>\n" );
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