document.write( "Question 641859: Train 1 leaves city A at 10:00 a.m. heading towards city B, 300 miles to the east, at 45 miles per hour. At 11:00 a.m., train 2 leaves city A from city B at 55 miles per hour. Which train will complete the trip first and when will it pass the other?\r
\n" ); document.write( "\n" ); document.write( "I got this so far:
\n" ); document.write( "R*T = D
\n" ); document.write( "(45)*(1) = 45 mi head start for train 1\r
\n" ); document.write( "\n" ); document.write( "(45)*T = (300 - 45)
\n" ); document.write( "T = 5.7 hrs for train 1\r
\n" ); document.write( "\n" ); document.write( "(55)*T = 300
\n" ); document.write( "T = 5.45 hrs for train 2\r
\n" ); document.write( "\n" ); document.write( "so train 2 completes the trip first but I don't know when it will pass train 1. Please help me!!!
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Algebra.Com's Answer #403880 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Train 1 leaves city A at 10:00 a.m. heading towards city B, 300 miles to the
\n" ); document.write( " east, at 45 miles per hour.
\n" ); document.write( "At 11:00 a.m., train 2 leaves city A from city B at 55 miles per hour.
\n" ); document.write( " Which train will complete the trip first and when will it pass the other
\n" ); document.write( ":
\n" ); document.write( "Let t = travel time of Train 2; (started at 11 AM)
\n" ); document.write( "then
\n" ); document.write( "(t+1) = travel time of Train 1 (left one hr earlier)
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\n" ); document.write( "You are right about which train will arrive first
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\n" ); document.write( "\"when will they pass each other\"
\n" ); document.write( "When they meet, the sum of the distances traveled will = 300 mi
\n" ); document.write( "55t + 45(t+1) = 300
\n" ); document.write( "55t + 45t + 45 = 300
\n" ); document.write( "100t = 300-45
\n" ); document.write( "100t = 255
\n" ); document.write( "t = 255/100
\n" ); document.write( "t = 2.55 hrs which is 2 + .55(60) = 2:33, from 11 am; 1:33 PM they meet
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