document.write( "Question 58886: An object is projected upward from the top of a tower. Its distance in feet above the ground after t seconds is given by s(t)=16t^2+64t+80. How many seconds wil it take to reach ground level? \n" ); document.write( "
Algebra.Com's Answer #40387 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! An object is projected upward from the top of a tower. Its distance in feet above the ground after t seconds is given by s(t)=16t^2+64t+80. How many seconds wil it take to reach ground level? \n" ); document.write( "I THINK THE FORMULA IS S = -16T^2+64T+80 WHEN IT IS THROWN UP. \n" ); document.write( "ASSMING SO... \n" ); document.write( "at t=0, when it is thrown up we have \n" ); document.write( "s=0+0+80=80 \n" ); document.write( "hence the tower is at 80' from ground. \n" ); document.write( "WHEN THE OBJECTS FALLS ON GROUND ITS DISTANCE FROM GROUND =0 \n" ); document.write( "S=0 \n" ); document.write( "-16T^2+64T+80=0 \n" ); document.write( "T^2-4T-5=0 \n" ); document.write( "T^2-5T+T-5=0 \n" ); document.write( "T(T-5)+1(T-5)=0 \n" ); document.write( "(T-5)(T+1)=0 \n" ); document.write( "T=5 SEC. \n" ); document.write( "IT WILL TAKE 5 SEC TO HIT THE GROUND. \n" ); document.write( " \n" ); document.write( " |