document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=641829>Question 641829</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if csc(theta)=13/5 and theta is in the second quadrant, what is sec(theta)? I have no clue how to do this, can you please help?\r<BR>\n" );
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document.write( "Thank you very much! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #403831 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=403831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if csc(theta)=13/5 and theta is in the second quadrant, what is sec(theta)? <BR>\n" );
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document.write( "csc(theta) = r/y, so r = 13 and y = 5<BR>\n" );
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document.write( "Solve for \"x\":<BR>\n" );
document.write( "x = sqrt[r^2-y^2] = sqrt(13^2-5^2] = sqrt[169-25] = sqrt(144) = 12<BR>\n" );
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document.write( "But x is negative in the sesond quadrant, so x = -12<BR>\n" );
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document.write( "Ans: sec(theta) = r/x = 13/(-12) = -13/12<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.  </SPAN>\n" );
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