document.write( "Question 641777: another help please? :(\r
\n" ); document.write( "\n" ); document.write( "x^2-3x-40=0
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Algebra.Com's Answer #403795 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Use the quadratic formula to solve for x\r
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\n" ); document.write( "\n" ); document.write( "Note: in the case of \"x%5E2-3x-40\", a = 1, b = -3 and c = -40\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%28-%28-3%29%2B-sqrt%28%28-3%29%5E2-4%281%29%28-40%29%29%29%2F%282%281%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283%2B-sqrt%289-%28-160%29%29%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283%2B-sqrt%289%2B160%29%29%2F%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283%2B-sqrt%28169%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283%2Bsqrt%28169%29%29%2F2\" or \"x+=+%283-sqrt%28169%29%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+%283%2B13%29%2F2\" or \"x+=+%283-13%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+16%2F2\" or \"x+=+-10%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+8\" or \"x+=+-5\"\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x+=+8\" or \"x+=+-5\"
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