document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=641738>Question 641738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assuming that each child has the probability 0.5 being a boy. Find the probability that a family of 4 children has:\r<BR>\n" );
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document.write( "a. exactly one boy<BR>\n" );
document.write( "b. 2 or 3 boys<BR>\n" );
document.write( "c. all girls and<BR>\n" );
document.write( "d. at least one boy </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #403778 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=403778\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are 2^4 or 16 outcomes of boys and girls, all the way from 4 girls to 4 boys.<BR>\n" );
document.write( "a) P(only 1 boy) = 4/16 or 1/4<BR>\n" );
document.write( "b) P(2 or 3 boys) = 6/16 + 4/16 = 10/16 = 5/8<BR>\n" );
document.write( "c) P(all girls) = 1/16<BR>\n" );
document.write( "d) P(at least 1 boy) = 15/16 </SPAN>\n" );
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