document.write( "Question 641700: Two supplementary angles differ by 44.Find the angles.
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Algebra.Com's Answer #403768 by MathLover1(20850) $\"\"$ $\"About$

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\n" ); document.write( "\n" ); document.write( "Supplementary angles add up to $\"180\"$ °.\r
\n" ); document.write( "\n" ); document.write( " $\"alpha%2Bbeta=180\"$ ..........1
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\n" ); document.write( "\n" ); document.write( " $\"alpha-beta=44\"$ ...........2\r
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\n" ); document.write( "\n" ); document.write( " $\"alpha%2Bbeta=180\"$ ..........1...solve for $\"alpha\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha=180-beta\"$ .......plug it in 2
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\n" ); document.write( "\n" ); document.write( " $\"180-beta-beta=44\"$ ...........2\r
\n" ); document.write( "\n" ); document.write( " $\"180-2beta=44\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"180-44=2beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"136=2beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"136%2F2=beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%2868=beta%29\"$ ....now find $\"alpha\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha=180-beta\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"alpha=180-68\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"highlight%28alpha=112%29\"$ \r
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