document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=641686>Question 641686</A>: <I><SPAN STYLE=\"word-break: break-all;\"> After 15 yrs, Salma will be four times as old as she is now. Determine her present age.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #403766 by </B><A HREF=/tutors/aboutme.mpl?userid=lenny460><B>lenny460(1073)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lenny460><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=lenny460><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=403766\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> After 15 yrs, Salma will be four times as old as she is now. Determine her present age.\r<BR>\n" );
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document.write( "Let Salma's age be n years.\r<BR>\n" );
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document.write( "After 15 years, Salma will be (n + 15) years\r<BR>\n" );
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document.write( "Therefore:\r<BR>\n" );
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document.write( "n + 15 = 4n\r<BR>\n" );
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document.write( "Subtract n from each side of the equation.\r<BR>\n" );
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document.write( "n + 15 - n = 4n - n\r<BR>\n" );
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document.write( "Combine like terms:\r<BR>\n" );
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document.write( "n - n = 0\r<BR>\n" );
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document.write( "4n - n = 3n\r<BR>\n" );
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document.write( "Therefore:\r<BR>\n" );
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document.write( "15 = 3n or\r<BR>\n" );
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document.write( "3n = 15\r<BR>\n" );
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document.write( "Divide each side by 3\r<BR>\n" );
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document.write( "3n/3 = 15/3\r<BR>\n" );
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document.write( "n = 5\r<BR>\n" );
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document.write( "Therefore:\r<BR>\n" );
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document.write( "Salma is 5 years old now.\r<BR>\n" );
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document.write( "In 15 years Salma will be (5 + 15) = 20 years.\r<BR>\n" );
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document.write( "Lennox Obuong<BR>\n" );
document.write( "Algebra Student<BR>\n" );
document.write( "Email: obuong3@aol.com </SPAN>\n" );
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